Question

2) If one of zeros of quadrotic polynomid
(k-1) ²+ k&t 1 as "-3" then find
value of k.​

Answer 1

Answer:

Value of k is 4/3.

Step-by-step explanation:

Since, -3 is a zero of quadratic polynomial (k-1)x² + kx + 1. Therefore,

(k-1)(-3²) + k(-3) + 1 = 0

or 9(k-1) - 3k + 1 = 0

or 9k - 9 - 3k + 1 = 0

or 6k - 8 = 0

or k = 8/6 = 4/3

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