Question

2. If tan 58° = x, then tan 32° =
(a) x-1 (6) 1
(
90
(d) *
If a cotA+b cosec = pand bcot 8 +​

Answer 1

Tan 58°Tan32° = 1

x×tan32° =1

tan32°= $\frac{1}{x}$

Hope it helps

Answer 2

Answer:

Hence the value of tan 32° is 1/x.

given:

tan 58° =x

To Find:

Find the value of tan 32°

Step-by-step explanation:

As tan 52° = x

let there be a triangle ABC right angled at C,

AB =1

BC = x

∠BAC = 52°

∠BCA = 32°

For tan ∠BAC :

perpendicular = BC = x

base  = AB = 1

So tan ∠BAC = tan 58°

=perpendicular/base

=x/1

For tan ∠BCA :

perpendicular = AB = 1

base  = BC = x

So tan ∠BCA = tan 32°

=perpendicular/base

=1/x

Hence the value of tan 32° is 1/x.