Question

2. If the product of zeros of the polynomial ?
ax2 - 6x - 6 is 4, find the value of a.​

Answer 1

Answer:

product of zeroes = c/a

-6/a=4

a=-6/4

a=-3/2

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Answer 2

Step-by-step explanation:

$a {x}^{2} - 6x - 6 \\ \\let \: \alpha \: and \: \beta \: are \: the \: zeroes \: of \: the \: polynomial \\ \\ now \\ \\ \alpha \times \beta = 4 \\ \\ \alpha \times \beta = \frac{constant \: term}{coefficit \: of \: {x}^{2} } \\ \\ \alpha \times \beta = \frac{ - 6}{a} \\ \\ 4 = \frac{ - 6}{a} \\ \\ 4a = - 6 \\ a = \frac{ - 6}{4} \\ \\ a = \frac{ - 3}{2}$