Question

(2) if the roots of 2x2 - 6x +k 0 are real and equal, find k.

Answer 1

Answer:

k = 9/2

Explanation:

compare 2x²-6x+k=0 with

ax²+bx+c=0, we get

a = 2 , b = -6 , c = k

Discreminant (D) = 0

[ Since, roots are real and equal]

b²-4ac = 0

=> (-6)² -4×2×k = 0

=> 36 -8k = 0

=> -8k = -36

=> k = (-36)/(-8)

=> k = 9/2

Therefore,

k = 9/2

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