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If x - 6x + 1 = 0 , then the value of
![{x}^{3} + \frac{1}{ {x}^{3} } {x}^{3} + \frac{1}{ {x}^{3} }](https://tex.z-dn.net/?f=+%7Bx%7D%5E%7B3%7D++%2B++%5Cfrac%7B1%7D%7B+%7Bx%7D%5E%7B3%7D+%7D+)
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Answered by
9
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★ Correct Question :-
- If x² - 6x + 1 = 0, then what is the value of x³ + (1/x)³
★ GivEn :-
★ To Find :-
Now, ➦
Answered by
7
Correct Question :
If x² - 6x + 1 = 0, then what is the value of
Given :
To Find :
Solution :
As, we are given :
By cubing both sides, we get :
By using identinty :
Now, we have :
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