Question

2. If x tan2 60 + cosec 41 = cot 45 + sec 49, then
find the value of x.​

Answer 1

x tan ^2 60 + cosec41 = 1 + sec(90 - 41)

3 x+ cosec41 = 1+ cosec41

3x = 1

x = 1/3

Answer 2

Answer:

1/3

Step-by-step explanation:

xtan^2 60+cosec 41=cot 45 + sec 49

x(√3)^2 + cosec 41= 1 + sec 49

3x = 1 + 1/cos 49 - 1/ sin 41

3x= 1+ 1/cos 49 - 1/ cos 49 [as sin(90- theeta)= cos theeta]

3x= 1

x=1/3.

I hope this will help.