2. if z varies jointly as x2 and the square root of y and if z=75 when x=5 and
4
y=9, find z when x=3, and y=16
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Step-by-step explanation:
It is given that z varies jointly as x and the square root of y if z=6 when x=3 and y=16, therefore,
z=kxy⇒6=k×3×16⇒6=k×3×4⇒12k=6⇒k=126=21
Thus, the general equation is z=21xy.
Since x=7 and y=4, therefore,
z=21xy=21×7×4=21×7×2=7
Hence, z=7 cm when x=7 and y=4.
Hope it will help you ❣️
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