Question

2. If zeroes of p(x) = 2x2

– 7x + k are reciprocal of each other, then find the value of k.​

Answer 1

$\huge \bold \color{green}{ \underline{ \underline \red{required \: answer : }}}$

$p(x) = 2 {x}^{2} - 7x + k$

given :- zeroes of polynomial are reciprocal to each other

$\bold{let \: \alpha \: and \: \beta \: are \: zeroes \: of \: polynomila}$

according to question..

$\bold{ \alpha = \frac{1}{ \beta } }$

we know that..

$\bold{product \: of \: \: zeroes = \frac{c}{a} }$

here..

$\bold{ \alpha \beta = \frac{k}{2} }$

$\bold{ \implies \frac{1}{ \beta } \times \beta = \frac{k}{2}} \: \: \: \: ( since \: \: \alpha = \frac{1}{ \beta } )$

$\bold{ \implies1 = \frac{k}{2} } \\ \bold{\implies \: k = 2}$

so value of k is 2

Answer 2

Value of k is 2..........!