Question

A cylindrical road roller made of iron is 1 m wide. It's dinner diameter is 54 cm and thickness of the iron sheet rolled into the road roller is 9 cm. Find the weight of the roller if 1 c.c. of iron weighs 8 gm.​

Answer 1

Answer:

PRINCE OF PERSIA - RIVAL SWORDS

Answer 2

Given:

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• Width of the road roller is 1 m
• Length/height of the cylinder is 100 cm
• Inner radius of the cylinder is 27 cm
• Thickness of the iron sheet is 9 cm

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To find:

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The weight of the roller if 1 c.c. of iron weighs 8 gm.

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Solution:

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Width of the iron sheet = 1 m = 100 cm

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We know that,

Volume of cylinder = (πR$^{2}$h – π$^{2}$) cm$^{3}$

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So, volume of the iron sheet used =

(πR$^{2}$h – π$^{2}$) cm$^{3}$

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= π(R$^{2}$ – r$^{2}$)h cm$^{3}$

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= [π(R + r)(R – r) h] cm$^{3}$

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= [3.14 × (36 + 27)(36 –27) × 100] cm$^{3}$

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= 314/100 × 63 × 9 × 100 cm$^{3}$

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= 178038 cm$^{3}$

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Hence, weight of the roller = 178038 × 8/1000 kgs

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= 1424.304 kgs