2) IfP (-6, -3) and Q (-1,9), then complete the following activity to find PQ. Activity: Let P(X1. y) and Q (2 y). X-6, y=-3, x2 = -1, y= 9 C-x=[-1)--6)1 = .... (1) -=[O)- -3)T =0 PQ -V Distance formula) ... (2) PQ =25 + 144[From (1) and (2)] PQ = 169 . PQ =
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Answer:
P(-6,-3),Q(-1,9)
PQ=
(−6−(−1))
2
+(−3−9)
2
=
25+144
=
169
=13
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