Math, asked by ravindratripathi8482, 9 months ago

2. In a hostel it costs 1800 to keep 50 children for 8 weeks. For what length of time did the cost of keep
90 children amount to 21060?
3. In how many days of working 8 hours each day, can 12 men do the same work as 10 men workin
hours m1d1h1/w1

Answers

Answered by Pablu
6

Answer:

52 weeks

15 days

Step-by-step explanation:

Solution 2

The hostel cost for 50 children for 8 weeks = rs.1800.

The hostel cost for 1 child for 8 weeks  = 1800/50

The hostel cost for 1 child for 1 week = 1800/50 × 8

So, the hostel cost for 90 children for 1 week = (1800 × 90)/(50 × 8)

The cost of keeping 90 children for x number of weeks = Rs. 21060

Thus,

(1800 × 90 × x)/(50 × 8) = 21060

x = (21060 × 50 × 8)/(1800 × 90)

x = 8424000/162000

x = 52

So, the answer is 52 weeks.

Solution 3

The work done by 10 men in 16 days working 9 hours per day would be equal to the work done by 12 men in x days

working 8 hours per day.

12*8*x =10*16*9

We will get the value of x = 15.

So they will need 15 days to complete the same amount of work.

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