Question

2. In a isosceles triangle , ABC, AB = AC and ∆A
∆B find ∆C.​

Answer 1

I think questions is incomplete.

There is atleast one value wont to be given.

so please chack the question and then send again.

Answer 2

Answer:

hello sudhanshu,

her's your answer

Step-by-step explanation:

given,

∠A = 90°

and

AB=AC

∠B = ∠C     (since, AB=AC and angles opposite to equal sides are equal)

Now,

∠A + ∠B + ∠C = 180° (by angle sum property)

∠A + ∠B + ∠B = 180° (BECAUSE ∠B = ∠C)

90 + 2∠B = 180° (given ∠A = 90°)

2∠B = 180-90

∠B = 90/2

∴∠B = 45°

AND

∠B=∠C=45°