Question

(2)
In A PQR, angle P = 60°, angle Q = 90° and QR = 6 root 3 cm, then find
the values of PR and PQ.​

Answer 1

Answer:

Let PQR is a right angle triangle

PQ=6cm,∠RPQ=60

∘

=∠P

tan60

∘

=

PQ

QR

⇒

3

=

6

QR

⇒QR=6

3

sin60

∘

=

PR

QR

⇒

2

3

=

PR

6

3

⇒PR=6

3

×

3

2

=6×2=12

∴ The length of QR is 6

3

cms

∴ The length of PR is 12 cms

solution

Answer 2

Given:

P = 60°

Q = 90°

QR = 6√3

To Find:

PQ, PR

Solution:

we know,

tan Ф = P / B

In PQR

tan 60° = RQ / PQ

√3 = 6√3 / PQ

PQ = 6√3 / √3

PQ = 6√3 / √3

PQ = 6 cm

sin Ф = P / H

Sin 60° = 6√3 / PR

√3/2 = 6√3 / PR

PR = 6√3 / √3/2

PR = 6 * 2 = 12cm

So, PR  = 12cm and PQ = 6cm.