2.
In a quadratic polynomial x2 - 6x, product of the zeroes is
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hey
cute
your answer is here
Hi there!
Here's your answer :-
Given - α and β are roots of x² - 6x + a
→ Sum of roots of quad. polynomial = - b / a = - (-6) / 1 = 6
α + β = 6
α = 6 - β -----(i)
Now,
3α + 2β = 20
3(6 - β) + 2β = 20
18 - 3β + 2β = 20
-β = 2
β = -2
Substitutin' value of β in eqn. (i) :-
α = 6 - (-2) = 6 + 2 = 8
→ Product of roots of quad. polynomial = c / a
α × β = a / 1
a = 4 × (-2)
a = -8
Hence, The required answer is :- [ - 8 ]
Hope it helps
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