Question

2. In a right triangle
ABC, right angled at B the
reatio of AB to Ac is live. Find the valuest-

(b) 2tan A / (1 - tan2A)​

Answer 1

Answer:

sorry

Step-by-step explanation:

Answer 2

Answer:

1

Step-by-step explanation:

We are given that,

In right triangle ABC, the ratio AB : AC = 1 : \sqrt{2}.

So, from the figure below, we get that,

\cos A=\frac{AB}{AC}=\frac{1}{\sqrt{2}}

i.e. \cos A=\frac{1}{\sqrt{2}}

\cos A=\cos 45

i.e. A = 45°

So, we have,

\frac{2\tan A}{1+tan^2A}=\frac{2\tan 45}{1+tan^245}

i.e. \frac{2\tan A}{1+tan^2A}=\frac{2\times 1}{1+1^2}

i.e. \frac{2\tan A}{1+tan^2A}=\frac{2}{2}

i.e. \frac{2\tan A}{1+tan^2A}=1

Hence, the value of \frac{2\tan A}{1+tan^2A} is 1.