2. In a right triangle
ABC, right angled at B the
reatio of AB to Ac is live. Find the valuest-
(b) 2tan A / (1 - tan2A)
Answers
Answered by
0
Answer:
sorry
Step-by-step explanation:
Answered by
3
Answer:
1
Step-by-step explanation:
We are given that,
In right triangle ABC, the ratio AB : AC = 1 : \sqrt{2}.
So, from the figure below, we get that,
\cos A=\frac{AB}{AC}=\frac{1}{\sqrt{2}}
i.e. \cos A=\frac{1}{\sqrt{2}}
\cos A=\cos 45
i.e. A = 45°
So, we have,
\frac{2\tan A}{1+tan^2A}=\frac{2\tan 45}{1+tan^245}
i.e. \frac{2\tan A}{1+tan^2A}=\frac{2\times 1}{1+1^2}
i.e. \frac{2\tan A}{1+tan^2A}=\frac{2}{2}
i.e. \frac{2\tan A}{1+tan^2A}=1
Hence, the value of \frac{2\tan A}{1+tan^2A} is 1.
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