Question

2. In a survey relating to reading habits of people in a town it was observed that 60% read
magazine A, 50% magazine B, 50% magazine C, 30% A and B, 20% B and C, 30% C and
A and 10% all the threes. In the fitness of the thing, state (i) what percentage read exactly
two magazines ? (ii) what percentage do not read any of the threes?
F​

Answer 1

Answer:

(1) 100%

(2) 60%

Step-by-step explanation:

A 60% means 60/100 = 3/5

B 50% means 50/100= 1/2

C 50% means = 50/100 =1/2

now add them all 3/5+1/2+1/2 = 16/10 means we can say total people is 16 and magazine readers in this is 10

then 2nd answer is (16-10)*100/10 = 60% NOW,

A+B = 30% = 3/10

B+C = 20% = 1/5

C+A = 30% = 3/10

now add all them = 3/10+1/5+3/10 = 8/10

means all magazine readers we have is 10 (from upper equestrian is also same) in which exactly two magazine readers is 8 but we know that all members are 16 then we need to make a percentage from use of total people...so 1st answer is --

(16-8)*100/8 = 100% is reading both magazines..

Answer 2

Step-by-step explanation:

please send me the answer of this question