Question

2) In a trapezium, if distance between parallel sides is 8 cm, and lengths of
the parallel sides are 13 cm and 9 cm respectively then find the area of
the trapezium?
​

Answer 1

Let us take a trapezium ABCD.

• The distance between the 2 parallel sides refers to the height of the trapezium

With respect to the above Diagram,

• DC = 13cm
• AB = 9cm
• Height = 8cm

Now that we have the measurements, by applying the formula, let us find the area of the trapezium.

Formula to use :-

$Area \: of \: the \: Trapezium = \dfrac{1}{2} \times height \times (sum \: of \: parallel \: sides)$

Substituting the values,

Area :-

$\dfrac{1}{2} \times 8 \times (13 + 9)$

$\dfrac{1}{2} \times 8 \times 22$

By cancellation,

$\dfrac{1}{ \cancel2} \times 8 \times \cancel{22}$

$8 \times 11$

$= 88 {cm}^{2}$

Therefore the area of the trapezium is 88cm²

Some more formulas :-

• Area of a triangle = ½ × Base × Height
• Area of a square = Side × Side =≥ (side)²
• Area of a rectangle = Length × Breadth
• Area of a parallelogram = Base × Height
• Area of a rhombus = ½ × Diagonal 1 × Diagonal 2