Math, asked by dineshsalunke22, 3 months ago

2) In a trapezium, if distance between parallel sides is 8 cm, and lengths of
the parallel sides are 13 cm and 9 cm respectively then find the area of
the trapezium?

Answers

Answered by Dinosaurs1842
4

Let us take a trapezium ABCD.

  • The distance between the 2 parallel sides refers to the height of the trapezium

With respect to the above Diagram,

  • DC = 13cm
  • AB = 9cm
  • Height = 8cm

Now that we have the measurements, by applying the formula, let us find the area of the trapezium.

Formula to use :-

Area \:  of  \: the \:  Trapezium =  \dfrac{1}{2}  \times height \times (sum \: of \: parallel \: sides)

Substituting the values,

Area :-

 \dfrac{1}{2}  \times 8 \times (13 + 9)

 \dfrac{1}{2}  \times 8 \times 22

By cancellation,

 \dfrac{1}{ \cancel2}  \times  8 \times  \cancel{22}

8 \times 11

 = 88 {cm}^{2}

Therefore the area of the trapezium is 88cm²

Some more formulas :-

  • Area of a triangle = ½ × Base × Height
  • Area of a square = Side × Side =≥ (side)²
  • Area of a rectangle = Length × Breadth
  • Area of a parallelogram = Base × Height
  • Area of a rhombus = ½ × Diagonal 1 × Diagonal 2

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