2. In a triangle ABC, E is the mid-point of median
AD. Show that ar (BED)= - ar(ABC).
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Answer:
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Step-by-step explanation:
AD is the median of ΔABC. Therefore, it will divide ΔABC into two triangles of equal area.
∴ Area (ΔABD) = Area (ΔACD)
⇒Area (ΔABD ) = (½) area (Δ ABC) ------------(1)
In ΔABD, E is the mid-point of AD.
Therefore, BE is the median.
∴ Area (ΔBED) = Area (ΔABE)
Area (ΔBED) = (1/2)Area (ΔABD)
Area (ΔBED) = (½ ) x(1/2) Area (ΔABC) [From (1)]
∴ Area (ΔBED) = (1/4)Area (ΔABC).
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Solution:
ar(BED) = (1/2)×BD×DE
Since, E is the mid-point of AD,
AE = DE
Since, AD is the median on side BC of triangle ABC,
BD = DC
DE = (1/2) AD — (i)
BD = (1/2)BC — (ii)
From (i) and (ii), we get,
ar(BED) = (1/2)×(1/2)BC × (1/2)AD
⇒ ar(BED) = (1/2)×(1/2)ar(ABC)
⇒ ar(BED) = ¼ ar(ABC)
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