A FORCE IF 400 N ACTING ON A CAR OF MASS 100KG ENABLES IT TO MOVE WITH A UNIFORM VELOCITY OF 60KMPH OVER A HORIZONTAL ROAD.THE COEFFICIENT OF FRICTION BETWEEN THE TYRE AND THE GROUND(G=10M/S^2)
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Answered by
8
Answer:
0.4
Explanation:
400=ux100x10
u=400÷1000
=0.4
Answered by
0
Explanation:
400=u(+10)100
u=400/1000
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