Question

2) In a triangle ABC, if 22A = 32B = 62C, then the measure of A is
a) 30° b) 750 c) 90° d) 60°


3) If M is the midpoint of hypotenuse AC of right angled triangle ABC then BM =>
a) AC b) BC c) AB
d) none of these

4) Prove that if two lines intersect each other, then the vertically opposite angles are equal.​

Answer 1

Step-by-step explanation:

2) In a triangle ABC, if 22A = 32B = 62C, then the measure of A is

2) In a triangle ABC, if 22A = 32B = 62C, then the measure of A isa) 30° b) 750 c) 90° d) 60°

2) In a triangle ABC, if 22A = 32B = 62C, then the measure of A isa) 30° b) 750 c) 90° d) 60°3) If M is the midpoint of hypotenuse AC of right angled triangle ABC then BM =>

2) In a triangle ABC, if 22A = 32B = 62C, then the measure of A isa) 30° b) 750 c) 90° d) 60°3) If M is the midpoint of hypotenuse AC of right angled triangle ABC then BM =>a) AC b) BC c) AB

2) In a triangle ABC, if 22A = 32B = 62C, then the measure of A isa) 30° b) 750 c) 90° d) 60°3) If M is the midpoint of hypotenuse AC of right angled triangle ABC then BM =>a) AC b) BC c) AB d) none of these

2) In a triangle ABC, if 22A = 32B = 62C, then the measure of A isa) 30° b) 750 c) 90° d) 60°3) If M is the midpoint of hypotenuse AC of right angled triangle ABC then BM =>a) AC b) BC c) AB d) none of these4) Prove that if two lines intersect each other, then the vertically opposite angles are equal.

Answer 2

Answer:

is given that D is the midpoint of BCDL⊥AB and DM⊥AC such that DL=DM

Considering △BLD and △CMD as right angled triangle

So we can write it as

∠BLD=∠CMD=90

∘

We know that BD=CD and DL=DM

By RHS congruence criterion

△BLD=△CMD

∠ABD=∠ACD(c.p.c.t)

Now, in ∠ABC

∠ABD=∠ACD

We know that the sides opposite to equal angles are equal so we get

AB=AC

Therefore, it is proved that AB=AC.