find the value of k,if the area of triangle formed by (-5,7)(-4,-5)(k,5) is 53 square units
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Step-by-step explanation:
The value of k = 4 is the correct answer.
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Answer:
We have,
Area of triangle ABC =1/2[X1(Y2-Y3)+X2(Y3-Y1)+X3(Y1-Y2)]
53=1/2[-5(-5-5)+-4(5-7)+k(7+5)]
53=1/2[(-5*-10)+(-4*-2)+(K*12)
53*2=50+8+12K
106=58+12K
106-58=12K
12K=48
K=48/12
K=4
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