Math, asked by Tejas1234567, 1 year ago

2) In ∆ ABC and ∆ PQR,
∠ ABC ≅ ∠ PQR, seg BD and
seg QS are angle bisector.
If l
l
(AD)
(PS)
=
l
l
(DC)
(SR)
Prove that : ∆ ABC ∼ ∆ PQR A

Answers

Answered by Anonymous
16
... Hope you got it.
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Answered by GauravSaxena01
1

Solution :-

The angle bisector of a triangle dividing one side into two segments; the ratio of the two segments is proportional to the ratio of the other two sides of the triangle.

According to the problem,

In triangle ABC, BD is the angle bisector

Then AD/DC=AB/AC ---------(I)

Similarly, in triangle PQR, QS is the angle bisector

Then PS/SR=PQ/QR ----------(II)

Given that AD/PS=DC/SR

Substitute AD=(DC.PS)/SR

On solving, AB/AC=PS/SR

Therefore AB/AC=PQ/SR

The sides are proportional to each other. Hence the triangle ABC~ triangle PQR.

==========

@GauravSaxena01

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