Physics, asked by moin2047, 1 year ago

4,6 & 8 Ω resistors are connected to the circuit in series to a 12 v battery calculate a) Total resistance of the circuit b) Electric current glows through the circuit c) Potential difference

Answers

Answered by harsh788892

mark as brainlist pal
hope it helps

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harsh788892: but bro fir to boards bhi hoga

moin2047: ha par hamara syllabus dusra hai

harsh788892: u r cbse??

moin2047: our boards exams are little late

moin2047: no state board

moin2047: but our syllabus is completely same as urs

moin2047: only exam conducting board is different

harsh788892: acha ok now i understood bro

moin2047: i too studied icse till grade 9 but changed for 10th

harsh788892: ok good

Answered by Flutterfield

Resistor 1=R1= 4ohm
Resistor 2= R2= 6ohm
Resistor 3=R3=8ohm
Voltage=12V
a) Total resistance of the circuit in series= Rs
Rs=R1+R2+R3
=4+6+8
=18ohm
b) Electric current glows through the circuit=I
I=V/R
=12/18
=2/3=0.66A
c) Potential Difference=V=12V

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