Question

2) In an A.P, the sum of three consecutive terms is 27 and their product is 504. Find the
terms. [Assume that three consecutive terms in A.P. are a-d, a, a + d.]
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Answer 1

Step-by-step explanation:

The terms are a-d , a , a+d

Their sum

a-d+a+a+d = 27

3a = 27

a = 9

a ( a - d )( a + d ) = 504

9 ( 9 - d )( 9 + d ) = 504

9 [ 9² - d² ] = 504

9 ( 81 - d² ) = 504

729 - 9d² = 504

-9d² = -225

d² = 25

d = 5

So the terms are

4 , 9 , 14

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