Question

2. In APQR ZR Is a divisor of IPR = 15, RQ = 20, PS = 12 then find SQ. P S R Ans:​

Answer 1

Shubham Anant Gholap Pagal Mnada Yes

Answer 2

Given that:-

In ΔPQR,

$PR = 15,$ $RQ = 20,$

$PS = 12$

To find:-

$SQ=?$

As, seg RS bisects ∠R,

By angle bisector theorem,

When a ray bisects a triangle's angle, it divides the opposing sides into proportional segments.

$=>\frac{PR}{PS}=\frac{RQ}{SQ}$

$=>\frac{15}{12}=\frac{20}{SQ}$

By cross multiplication,

$=>SQ=\frac{12\times20}{15}$

$=>SQ=4\times4$

$=>SQ=16 units$