Question

2. In graph-10, find the values ofAC, AB and BC​

Answer 1

Answer:

In△BEC:

∠EBC+∠BEC+∠BCE=180∘

⟹55∘+x+∠BCE=180∘

⟹∠BCE=125∘−x−(1)In△BDA

⟹55∘+75∘+∠BAD=180∘

⟹∠BAD=50∘

∵∠A=∠C

⟹∠BAD=∠BCE

⟹∠BCE=50∘

puttingin(1)

⟹50=125−x

⟹x=75∘