Question

2) In ∆ PQR, angle Q=90° and PQ = 5cm and PR=13cm , Find QR. please say fast it's urgent plz.... if any one says the correct answer i will follow u plz...​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Step-by-step explanation:

given,

Q=90°

PQ=5Cm

PR=13Cm

QR=X

by Pythagoras theorem

(13)^2=(x)^2+(5)^2

169=x^2+25

x=√(169+25)

x=√144

x=12Cm

QR=12Cm

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