Question

2. In rectangle ABCD. angleAEB-90 and angleCFD=90, DF-7.
FC_24. AE-15 then find perimeter of rectangle
ABCD?​

Answer 1

Step-by-step explanation:

This is the figure for the required problem. In order to find the Perimeter, we need to find its breadth(BC)

So in right △ ABC,

AC2=BC2+AB2 …[Pythagoras’s Theorem]

BC=AC2−AB2−−−−−−−−−−√

BC=132−122−−−−−−−−√

BC=169−144−−−−−−−−√

BC=25−−√

BC=5 m

Now we have the breadth of the rectangle, Thus the Perimeter of this rectangle ABCD is

P=2(l+b)

P=2(AB+BC)

P=2(12+5)

P=2(17)

P=34 m

Answer 2

Answer

AC= 25

CD= 7

By pythagoras theorem,

AC

2

= AD

2

+ DC

2

625= AD

2

+ 49

AD

2

= 576

AD= 24

Hence,

Perimeter =

2(7+

24)=

62units