2.
In the adjacent figure.
(i) Are AAOB congruent to ADOC?
(2) Are AABC and ADCB congruent?
Also identify the relation between corresponding elements and
give reason for your answer.
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Answer:
Consider ∆AOB and ∆DOC
angleAOB = angleDOC. (vertically opposite)
angleBAO = angleCDO =30°
As two angles are equal third angle must be equal by angle sum property.
In ∆OBC
As OBC is isosceles triangle
OB=OC (sides opposite to equal angle are equal)
So,
angleAOB = angleDOC. (vertically opposite)
angleABO = angleDCO. (from above)
OB=OC
∆AOB is congruent to ∆DOC by ASA congruence
AB=DC by CPCT
AO=OD by CPCT
Consider ∆ABC and ∆DCB
AB=AC
AO+OC=DO+OB
AC=BD
BC=BC (common)
So, ∆ABC is congruent to ∆DCB by SSS congruence
Hope you find my answer helpful
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