Question

2. In the adjoining fig., ABCD is a trapezium, in
which AB II-DC, CE I AB. If DC = 12 cm,
AE = 14 cm, EB = 6 cm and non parallel side
BC = 10 cm, then find the area of trapezium.​

Answer 1

Answer:

Prove that:

Area of a trapezium ABCD = {¹/₂ × (AB + DC) × h} square units.

Proof: Area of a trapezium ABCD

= area (∆DFA) + area (rectangle DFEC) + area (∆CEB)

= (¹/₂ × AF × DF) + (FE × DF) + (¹/₂ × EB × CE)

= (¹/₂ × AF × h) + (FE × h) + (¹/₂ × EB × h)

= ¹/₂ × h × (AF + 2FE + EB)

= ¹/₂ × h × (AF + FE + EB + FE)

= ¹/₂ × h × (AB + FE)

= ¹/₂ × h × (AB + DC) square units.

= ¹/₂ × (sum of parallel sides) × (distance between them)

Step-by-step explanation:

Answer 2

Answer:

Here is ur ans...

Step-by-step explanation:

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