2. In the adjoining figure, area of ABE is equal to the area of parallelogram ABCD. If altitude EF is 16 cm long, find the length of the altitude of the parallelogram to the base AB of length 10 cm. What is the area of AAMD, where M is mid-point of side DC?
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Answer is 306 m^2, where M is mid-point of side DC?
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Answer:
step by step
area of triangle =area of parallelogram
area of triangle =½×base ×height=80 cm
by condition,Base ×height=80cm
10×height=80
height=80÷10
height=8cm
m is mid point of dc
therefore dc=10cm
dm=5cm
area of triangle AMD=½×base×height
½×5×8
20cm²
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