Question

2. In the figure, diameter TK chord RS at the point P.
RS = 6 cm, KC =5 cm. Find I(PT).
(1) 9 cm (2) 6 cm (3) 8 cm (4) 10 cm​

Answer 1

Answer:

3) 8 cm. is torrectaswerhe

Answer 2

Answer:

PT=9cm

Option 1

Step-by-step explanation:

Radius of circle is KC=CS=CT=5cm

Given RS=6cm

So, RP=PS=3cm

In triangle CPS,

CP²+PS²=CS²

CP²+3²=5²

CP²=4²

CP=4cm

Now, PT=PC+CT

=4+5=9cm

So, PT=9cm