Question

Q 47 Which of the following options is correct about
leclanche cell?
Ops: A
All of the mentioned options
B.
At anode, Zn(s) gets converted to Zn
ion.
C.
Ammonia is not liberated as gas as it
combines with Zn ion to from
2+
Zn(NH3)4
D.
At cathode, Mnoz reacts
with
ammonium ion and MnO(OH) and NH3
is formed​

Answer 1

Option B is the right answer . At anode, Zn(s) gets converted to Zn ion.

Answer 2

Answer:

B.

At anode, Zn(s) gets converted to Zn

ion.

Explanation:

anode (oxidation of Zn):

$Zn --- > Zn^{2+} + 2e^{-} | E_{0} = 0.76$ Volts.

The chemical process which produces electricity in a Leclanché cell begins when zinc atoms on the surface of the anode oxidize, i.e. they give up both their valence electrons to become positively charged $Zn^{2+}$ ions.

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