Question

2) In the given figure, AA1A1A2 =A2A3 = A3C, IF B1A1 || CB, then Ay divides AC in the ratio
a) 4:1
b) 1:3
c) 1:4
d) 1:2
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Answer 1

Answer:

The correct answer is Option (b) 1:3

Step-by-step explanation:

Given: In the given figure, AA1A1A2 =A2A3 = A3C, IF B1A1 || CB, then Ay divides AC in the ratio

To find: Find the ratio

calculations:

AB = AA1+A1A2+A2A3+A3B - EQUATIONAL

And as the question demands,

AA1 = A1A2= A2A3 = A3B

We can make the equation1 as,

AB = AA1+AA1+AA1+AA1

So, AB = 4AA1 - equation 2

Also, in such

AB is nothing but AA1 + A1B

AA1+A1B = 4AA1

A1B = 3AA1

$\frac{AA1}{A1B}$ = $\frac{1}{3}$

Therefore, AA1: A1B = 1:3

so, $A_{1}$ divides AB in the ratio of 1:3.

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