Question

2. In the given figure, if AB || DE, ABC = 55° and (CDE = 160°, then find BCD​

Answer 1

Answer:

BCD = 35°

Step-by-step explanation:

Given information:

ABC = 55°

CDE = 160°

AB is parallel to DE.

We can extend the line DE towards the line BC as shown in the image attached below.

Let the point that DE meets BC be F.

From the figure,

ABE = BED (Alternate angles)

Therefore, BED = 55°

BED + CED = 180° (Since, BC is a straight line)

=> 55° + CED = 180°

=> CED = 180 - 55 = 125°

Also,

FDC + CDE = 180° (Since, FE is a straight line)

=> FDC + 160° = 180°

=> FDC = 180° - 160° = 20°

Now,

CED + FDC + BCD = 180° (Sum of the angles of a triangle = 180°)

125° + 20° + BCD = 180°

=> BCD = 180° - (125° + 20°)

=> BCD = 180° - 145°

=> BCD = 35°

Answer 2

above pic is the answer