Question

2. In the given figure, RQ is a tangent to the circle with
centre 0. If SQ = 6 cm and QR = 4 cm, then OR is
equal to
[CBSE 2014)
(a) 2.5 cm
(b) 3 cm
(c) 5 cm
(d) 8 cm

Answer 1

Answer:

c) 5 cm is the answer

We know that Radius is perpendicular to the tangent

Therefore ∆OQR is a Right Triangle

OQ² + QR² = OR²

OQ = ½QS as QS is the diameter of the circle

Therefore OQ = 3 cm

QR = 4 cm

Therefore OR = √16 + 9

OR = √25

OR = 5 cm

Thank you