Math, asked by mniamo16, 10 months ago

2 is a root of ax^4-11x^3+ax^2+13x+2. What is the value of a?

Answers

Answered by Anonymous
4

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Anonymous: thanks for marking my answer as Brainliest answer...
Answered by RishikaPaul
2
a (2)^4-11 (2)^3+a (2)^2+13 (2)+2=0

16a-88+4a+26+2=0

20a-60=0

20a=0+60

20a=60

a=60/20

a=3
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