Question

2 is the zero of polynomials p(x) = ax^2 - 3(a - 1)x - 2 then value of a is : (a) 1 (b) 2 (c) -1 (d) - 2
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Answer 1

Answer:

p(x)=ax²-3(a-1)x-2

(a)1 (b)2 (c)-1 (d)-2

soln=p(x)= ax²-3(a-1)x-2

1. p(1) =a(1²)-3(a-1) 1-2=2a+3

2. p(2)=a(2²)- 3 (a-1)1-2= a+3

3. p(-1)=a(-1²)-3(a-1)-1-2=2a

4. p(-2)=a(-2²)-3(a-1)-2-2=a-1