Math, asked by premsing77, 5 months ago

2. Jaimin takes Rs. 10000 at 12% per year as rate of interest, for 2 years. How much interest he

has to pay at the end of two years?​

Answers

Answered by hriddho
3

Answer:

Rs12400

Step-by-step explanation:

Simple interest=12% of 10000

=12/100*10000

=Rs1200 per year

1 year=Rs1200

So, At the end of 2 years=Rs1200*2

=Rs2400

Total income=10000+2400

=Rs12400

Please mark me as the brainliest

Answered by ItzDinu
15

 \huge \mathscr{\orange {\underline{\pink{\underline {Answer:-}}}}}

GIVEN :-

Principal = ₹10,000

Rate = 12%

Time = 2 Years.

TO FIND :-

How much interest he has to pay at the end of two years?

SOLUTION :-

Principal = ₹10,000

Rate = 12%

Time = 2 Years.

S.I = P×R×T/100

= 10,000×12×2/100

= 2,400

So, Interest he Has to pay at the end of two years = 2,400.

  • Please Give me Thanks •
Similar questions