2. Jhonny is tossing a ball vertically into the air, if he is 5ft tall and he didn’t catch the ball which he tosses 4.89 m above the ground. Find the final velocity of the ball if hits the ground after 3.34 s?
Answers
Answer:
Explanation:
We are asked to find the total time t the ball was in the air. We are thus essentially solving for t in the equation 6=−16t2+30t+5.
To solve for t we rewrite the equation above by setting it equal to zero because 0 represents the height. Zero height implies the ball is on the ground. We can do this by subtracting 6 from both sides
6−6=−16t2+30t+5−6
0=−16t2+30t−1
To solve for t we must use the quadratic formula:
x=−b±√b2−4ac2a
where a=−16,b=30,c=−1
So...
t=−(30)±√(30)2−4(−16)(−1)2(−16)
t=−30±√836−32
This yields t≈0.034,t≈1.84
Notice: What we ultimately found were the roots of the equation
and if we were to graph the function y=−16t2+30t−1 what we will get is the path of the ball.
Explanation:
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Answer
t≈0.034,t≈1.84
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