Question

2. Joseph jogs from one end A to the other end B of a straight
300 m road in 2 minutes 30 seconds and then turns around
and jogs 100 m back to point C in another 1 minute. What are Joseph's average speed and velocities in jogging from a to b from here to C
Joseph's average speeds and velocities in jogging (a) from A to
B and (b) from A to C?​

Answer 1

Answer:

Velocity = dispacement / time

Speed = distance / time

a) when he jogs from A to B on a straight road,

displacement = distance = 300m

time = 2 minutes 30 seconds = 150 s

velocity = 300/150 = 2 m/s

speed = 300/150 = 2m/s

b)when he jogs from A to B and turns back to C,

displacement = 300-100 = 200m

distance = 300+100 = 400m

time = 3 minute 30 second = 210 s

velocity = 200/210 = 20/21 m/s

speed = 400/210 = 40/21 m/s

Explanation:

Answer 2

Explanation:

From pont A to B

Distance covered=300m

Displacement=300m

Time taken=2 min 30 sec=(2×60)+30=150 sec

Average speed=  Distance covered /Timetaken  =  150/300=2m/s

Average velocity=  Displacement/ Timetaken  =  150/300 =2 m/sec

From point A to C

Distance covered=300+100=400m

Displacement=300−100=200m

Time taken=3 min 30 sec=(3×60)+30=210 sec

Average speed=  Distance covered /Timetaken =210/400=1.9 m/s

Average velocity=  Displacement /Timetaken=210/200=0.95 m/s

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