Question

2. Joseph jogs from one end A to the other end B of a straight
300 m road in 2 minutes 30 seconds and then turns around
and jogs 100 m back to point C in another 1 minute. What are
Joseph's average speeds and velocities in jogging (a) from A to
B and (b) from A to C?
A​

Answer 1

Answer:

1.9 m/s

Explanation:

d1 = 300m

t1 = 2 min 30 sec = 150 seconds

d2 = 100m

t2 = 1 min = 60 seconds

therefore, average speed/ velocity

= (d1 + d2) / (t1 + t2)

= (300 + 100) / (150 + 60)

= 400 / 210 = 1.9 m/s

Hope it is correct, and hope this helps :)

Answer 2

Answer:

It is given that Joseph jogs on a straight road of 300m in a time interval of 2 minutes and 30 seconds, which is equal to 150seconds. Therefore, when Joseph jogs from point A to point B, he covers a distance of 300m in time of 150seconds. Hence, his average speed is 300m150s=2ms−1.