Question

2 kg attached to a spring of force constant 260 newton per metre makes hundred situation what is the time period

Answer 1

Time taken for 100 oscillations is 55.25 s.

Explanation:

Given data:

Mass "m" = 2 kg

Force constant "k" = 260 N/m

Number of oscillations "f"  = 100 oscillations

Solution:

• Angular velocity is

ω = √(k/m)

ω = √(260/2)

ω = √130

ω = 11.4 rad/s

• Frequency of oscillations.

f = ω/2π

f = 11.4/(2×3.14)

f = 1.82 Hz

• Time taken is given by-

t = f'/f

t = 100/1.82

t = 55.25 s

Time taken for 100 oscillations is 55.25 s.

Also learn more

What is angular momentum???

https://brainly.in/question/6710222