Chemistry, asked by jangidkhushi19, 6 months ago

2 kg of 30 percent aqueous solution of urea by mass is mixed in 8 kg of 70 percent aqueous sol of urea by mass .what is the final mass percent?

Answers

Answered by vadu1010
0

Answer:

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Explanation:

Molality=GMWtWt×Wt of water1000

Weight of Water is 100−30=70g

Molality=6030×701000 = 7.1 m

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