Question

2 kg of substance receives 500 kj undergoes a temp change from 100 c to 200 c the avg specific heat of substance during the process is

Answer 1

Answer:

Energy Required= Mass x S.h.c x change in temperature

E=mc◇T

C= E/m◇T

E= 500×10^3j

m= 2kg

◇T= 200-100=100°C

C=500000/2x100

C=2500j/kg°C

Answer 2

Average specific heat capacity is the amount of heat required to raise temp. of 1g substance by 1°c(celcius)

So, coming to formula of specific heat capacity i.e.,

c=Q/m(deltaT)

where, c=specific heat.

Q= heat(in joule)

m= mass of substance

deltaT= change in temperature(T2-T1)

So in question it is given that heat given to substance is 500kj or 500 ×10³ joule, whereas given that mass of substance is 2kg and given that temperature change of substance is from 100 to 200°c

i know you will think that when everything is taken in SI unit then why not i had considered temperature also in si unit that is kelvin, so i had done so because change in temperature in kelvin scale is equal to change in temperature in celsius scale...so when you will find T2-T1, then in both celsius and kelvin you will get same value...so it's better to use direct given data...

Put every values in above formula, you will get

c= 2.5×10³ joule/kg-K

Note: I am writing kelvin in final formula because....everything is in si unit so also take temperature in si unit that is kelvin.....but while solving consider temperature in celsius and it will be easier for you to solve then....

Please if you face any problem or any doubt...then comment.....

Good luck.....