Question

2) LACB is
inscribed in arc ACB of
with centre O If LACB=65
Find m (arc ACB) =
​

Answer 1

Answer: 230^{\circ}230

∘

Step-by-step explanation:

Since, Here the angle abc is inscribed in arc of circle with Center O,

Also, m\angle ACB = 65^{\circ}m∠ACB=65

∘

⇒ By the Central angle theorem,

m\angle ABC = 2 \times m\angle ACB = 2 \times 65^{\circ} = 130^{\circ}m∠ABC=2×m∠ACB=2×65

∘

=130

∘

Thus, the length of major arc ACB = 360^{\circ} - 130^{\circ} = 230^{\circ}360

∘

−130

∘

=230

∘