2 lead Sphears have radii in the ratio 1 : 2 and have the same linear momentum.What is the ratio of their kinetic energy?
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Answer:
KE = 1/2mv^2
p = mv
KE = (p^2)/2m
Since they have same 'p'
We can write
KE1:KE2 = m2:m1
Mass is directly proportional to the volume
m ∝ r^3
m2:m1 = (r2 : r1) ^3 = (2:1)^3 = 8:1
as KE1:KE2 = m2:m1 = 8:1
KE1:KE2 = 8:1
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