Physics, asked by HarshadTambvekar, 5 months ago

2. Let the velocity of the object be, when
it reaches point B. having fallen through a
distance x.
u= 0, S = X, a = g
v=u'+ 2as
1² = 0 + 2gx
..K.Em = m2)
K.E. = mg
Height of the object when at Bh-x
..P.E. = mg (h-)
P.E. = mgh - mgs
.. Total Energy T.E. = K.E. + P.E.
= mx + mgh - mgx
.: T.E. = mgh





why there is P.E. =mgh- mgx​

Answers

Answered by Anonymous
2

Answer:

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