Question

2. Limestone dissolves in hydrochloric acid for form calcium chloride, carbon dioxide, and water. How many moles of HCl are required to dissolve 205g of limestone? How many moles of water are formed? Note: Do not copy phase other people answer, write or type down the answer or solution step by step and explain why Note: A fool "expert" turn 205g to 2.5g so try not to confuse me, please

Answer 1

Answer:

CaCO3 + 2HCl -----> CaCl2 + H2O + CO2.

2.5g? g

Mass of CaCO3= 40+12+3(16)=52+ 48= 100.

Molar mass of CaCO3=100g.

Mass of CaCl2= 40 + 2(35.5)= 40+ 71= 111.

Molar mass of CaCl2=111g.

Mass of CaCO3 (g) Mass of CaCl2 (g)

For 100g of CaCO

3

, 111g of CaCl_2$$ is formed.

let for 2.5g of CaCO

3

, x g of CaCl

2

is formed.

Thus, by cross multiplication,

x=111×2.5/100=2.775g=2.78g

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