Question

2: Line segments AB and CD intersect at O such that AC ∥ DB. It ∠CAB = 350 and ∠CDB = 550. Find ∠BOD. ​

Answer 1

Answer:

good question  but idont know

Step-by-step explanation:

Answer 2

Answer:

We know that AC parallel to BD and AB cuts AC and BD at A and B, respectively.

∠CAB = ∠DBA (Alternate interior angles)

∠DBA = 35°

We also know that the sum of all three angles of a triangle is 180°.

Hence, for △OBD, we can say that:

∠DBO + ∠ODB + ∠BOD = 180°

35° + 55° + ∠BOD = 180° (∠DBO = ∠DBA and ∠ODB = ∠CDB)

∠BOD = 180° – 90°

∠BOD = 90°